What is the amount of lime contained in a 100-lb container of calcium hypochlorite (65%)?

Prepare for the Texas Class D Water License Exam with flashcards and multiple choice questions designed to improve your understanding. Learn through detailed hints and explanations to enhance exam readiness!

To determine the amount of lime in a 100-lb container of calcium hypochlorite (with a purity of 65%), it's essential to first understand the composition of calcium hypochlorite.

Calcium hypochlorite, often used as a disinfectant and for water treatment, contains both calcium and hypochlorite ions, and its formula is typically represented as Ca(OCl)₂. The term "lime" in this context usually refers to calcium hydroxide (Ca(OH)₂) that is produced when calcium hypochlorite is dissolved in water.

The calculation to find the actual amount of lime can be approached by considering the available percentage of calcium hypochlorite in the container. Since the container is 100 lbs and consists of 65% calcium hypochlorite, the quantity of the active chemical is:

0.65 x 100 lbs = 65 lbs of calcium hypochlorite.

From the calcium hypochlorite composition, it is understood that the lime portion is derived primarily from the calcium present. Each mole of calcium hypochlorite provides lime based on stoichiometric ratios in chemical reactions.

When working with the assumption that we can derive lime equivalently from the calcium hyp

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